Question

molecular mass (g) mmoles equivalents density g/mL 20°C) (mL) reagent weight 138.17 60.052 0.562 acetic acid 0.437 nitric acid 63.012 0.360 (70% soln wt/wt) theoretical product 4-nitroveratrole 183.16 melting point of 4-nitroveratrole Select the name of the catalyst used for this reaction, if there was no catalyst used, select none:

can someone help me with these calculations I'm having trouble with the mol to vol for veratrole and the ml to mass for the others.

Answer 1

molecular density vol (mL) 0.520 reagent mass (g) mmoles equivalents veratrole acetic acid nitric acid weight 138.17 60.052 (g/mL 20°C) 1.08 g/mL 1.05 g/mL 1.41 g/mL 0.562 0.459 7.6 0.437 63.012 0.508 0.360 (70% soln wt/wt) theoretical product 4-nitroveratrole 183.16 melting point of 4-nitroveratrole Select the name of the catalyst used for this reaction, if there was no catalyst used, select none

Explanation:

Density of veratrole is 1.08 g/mL. Convert mass of veratrole into volume using density.

Volume = mass/density

Substitute, mass as 0.562 g and density as 1.08 g/mL

Volume = (0.562 g) / (1.08 g/mL)

Volume = 0.520 mL

Therefore, volume of veratrole is 0.520 mL.

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Density of acetic acid is 1.05 g/mL. Convert volume into mass using density.

Mass = volume x density

Mass = (0.437 mL) x (1.05 g/mL)

Mass = 0.459 g

Calculate mmol from mass in grams.

Mmol of acetic acid = mass / (molar mass of acetic acid in g/mol) x (1 mol / 1000 mmol)

Mmol of acetic acid = (0.459 g) / (60.05 g/mol) x (1 mol / 1000 mmol)

Mmol of acetic acid = 7.6 mmol

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Density of nitric acid (70%) is 1.41 g/mL. Convert volume into mass using density.

Mass = volume x density

Mass = (0.360 mL) x (1.41 g/mL)

Mass = 0.508 g

Calculate mmol from mass in grams.

Mmol of nitric acid (70%) = mass / (molar mass of nitric acid in g/mol) x (1 mol / 1000 mmol)

Mmol of nitric acid (70%) = (0.508 g) / (63.01 g/mol) x (1 mol / 1000 mmol)

Mmol of nitric acid (70%) = 8.1 mmol