Question

Compounds Molecular Density | Amounts moles Weight or used concentration (gm/mL) Cyclohexanol 0.9624 2.1 mL 20 mmol g/mol Phosphoric 97.994 1.88 0.7 ml 0.0134 acid g/mol (1.316 g) mol Sodium 84.0066 2.16 3 mL 0.0771 Bicarbonate | g/mol (6.48g) mol Anhydrous 110.98 2.15 2 scoops N/A calcium g/mol of micro (can't chloride spatula measure) Calculations of moles Ex) phosphoric acid Mass = Density x Volume = 1.88 x 0.7 = 1.316 g Moles= 97.994 g/mol x 1/1.316 = 74.46352584/mol → 1/ 74.46352584 mol = 0.0134293936 mol = 0.0134 moles Observed Temp or Mass of Alkene Distillate collected Distillate V-1 48 – 60 °C (Increase) 0.21 g Distillate V-2 | 68 - 66 °C (Decrease) 0.368 g

Can someone please help me how to calculate the theoretical yield from this chart?

I am so confused

This is the chart that I was given and Distillate V-2 is the last part of the chart. This is the part of preparation and reaction of alkene lab, and only using Distillate V-2 not V-1.

Answer 1

The given seachon is a dehydoahon reachion. он Hароy phosphoic acid Co7 oL 1316 8) cyclohexanol C 2. mL) cyclobexene of cyclohex an ol gives I mole of cyclohexene AcCooding to deachon , i mole 20 mmol of cyclobexcnol is used. Незе, of cyclohexcanol pooduce 2o mmo of cyclohexene i mole of cyclohexene 82 g of cyclohexene o.082 of cyclohexene cy clobexene e .. Cycloboxene = (20o082 = 1-G4 a 2o mmo Theooescal ^ield = }-6 g : . cyclohexene Deneity Amoun foomed Moles O.81 9/mL 20 mmo l Heve, NaH CO3 Cac)a is used duoing oedchon coook up paocess