Question

I was wondering if anyone could help with finding the theoretical yield? i need to get the Limiting Reagent to find the theoretical yield. it would be appreciated thanks!

cyclohexanol MW: 110.16

cyclohexene MW: 82.14

Walol. 2. Cyclohexanol and especially cyclohexene are flammable liquids. Do not heating source in this experiment som stalo tento omos nopo of videos bos bosohoo Physical constants Cyclohexanol Cyclohexene bp (°C) 161 density (g/mL) 0.960 0.810 83

Answer 1

Here in this reaction, Cyclohexanol forms cyclohexene in the presence of phosphoric acid.

Cyclohexanol ==> cyclohexane ; catalyst = phosphoric acid

Hence only one reagent is available, Phosphoric acid is a catalyst. So limiting reagent is cyclohexanol.

Taken 20 mL of cyclohexanol, density = 0.960 g/mL

weight of taken cyclohexanol = volume x density

= 20 mL x 0.960 g/mL

weight of taken cyclohexanol = 19.2 g

Moles of cyclohexanol = weight of cyclohexanol taken/ molar mass of cyclohexanol

= 19.2 g/110.16 (g/mol)

Moles of cyclohexanol = 0.1743 mole

1 mole of Cyclohexanol gives 1 mole of Cyclohexene

110.16 g/mol of Cyclohexanol gives 82.14 g/mol of Cyclohexene

1 of Cyclohexanol gives 82.14 (g/mol)/110.16 (g/mol) of Cyclohexene

19.2 g of Cyclohexanol gives {82.14 (g/mol)/110.16 (g/mol)} x 19.2 g of Cyclohexene

19.2 g of Cyclohexanol gives 14.3163 g of Cyclohexene

Theoretical yield = 14.3163g