Question

how do I get the molar ratios between NaBr, 1-butanol and H2SO4 used in the experiment sn2 reaction 1-bromobutane
Moles:
NaBr: 0.0275
Butanol: 0.0216
H2SO4: 0.00840

Experiment: 08 The S2 Reaction: 1-Bromobutane Substitution nucleophilic bimolecular (SN2) reactions can be utilized to conver

butanol is the limiting reagent

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Answer #1

Answer) The table drawn below explains the molar ratio calculation:

Answer) the following reaction (S.2) takes place: → CH₂ chethH oH & Na Br + H₂SO4 → CH CH chcH₂ Br + NaHoa + H₂O

os molis. steps to calmlate molar Ratio - i sivide moles of each species by species with I least Number of mo 11) corvert the

Moles Ratio of Molus whole No. species Naber 0.0275 0.0 2750.00 840 3.27 (3.2.7 x4) 13 - 0.02160.00 840 I (2.57x4) 0.0216 But

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