Question

Q1 A 25.0 cm glass rod initially at a temperature of 0 °C is placed in hot water where it expands in length by 0.131 mm. Glass has a coefficient of linear thermal expansion of 9.0 x 10-6K-. What is the temperature of the water (in °C)?

Please show all steps even something minor like conversions.

Answer 1

change in Length of glass L = Lol 1+ MAT] initial temperature is = 273.15 K = 0.0131cm ALS 0 131mm x 1cm - 10mm La Lo= LOKAT AL - LOLAT >> 0.0131cm = 25cm x 9 x 106 (T-273.15k) - 6 3 T-273.15K = 58.22 T = 331.37 k. To 331:37 - 273.15.C T= 58.22°C .