If you dissolve 3 "units" of Pb(NO3)2, how many particles will be in the solution?
Pb(NO3)2 ---------------> Pb2+ + 2 NO3-
So,
1 unit of Pb(NO3)2 = 3 partilcles
Hence,
3 units of Pb(NO3)2 = 3 x 3 partilcles = 9 particles
Therefore,
If we dissolve 3 "units" of Pb(NO3)2, 9 particles will be in the solution.
If you dissolve 3 "units" of Pb(NO3)2, how many particles will be in the solution?
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