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MS ID a minimum of two fragments excluding M Relative Intensity M : mle Nitrogen: Yes/No Halogen(s): 50 100 IR Label the peak
What is the structure of the molecule for Integrated Spectra Problem #1?. Deduce it by using the molecular mass (M+) and frag
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Answer #1

step- 54 o IHNHR data Interpretation : 5H (multplit) in range 7-8 ppm indicate mono substituted. Aromatic compone gh quarteMass spectra PeoLC — = 139 м/, Moje tell (on •No Meprogen No Halogen |cs Scanned with CamScanner

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