Question

A 1,075 N pole is held in place by a light wire at an angle = 24.5° to the horizontal as shown in the figure. The pole is attached to a pivot at the bottom, and a mass of weight w = 2,375 N hangs from its top. The pole makes an angle of d = 65.5º with the horizontal. Assume the pole is uniform. m (a) Find the tension in the supporting wire (in kN). KN (b) Find the components of the reaction force (in kN) exerted by the floor on the pole. horizontal component: magnitude KN direction ---Select-- vertical component: magnitude direction ---Select--- V KN

Answer 1

The free body diagram fot pole is, B 24.5 EMA a) -- 24.5 -O 2005 D C 2375 N 90-0 24.5 T(1). - 1075 sin(24.5) { - Ax 1075N A 2375 * sin(24.5) l=0 445.795 984.896) 630 2 T() 222.898 984.896 20 - 3 T T= 1207.794 T- 161b + N. = 1.61*10'N T-1.61 KN b The horizontal component: Sfx=0 Ax - Tos 24.5 =0 Ax Toż4.5 Ax 3 = 1.61 *10 * Coo 24.5 Ax = 1465.04 i AX = 1.465 KN : The vertical component : Efjzo Ay – 1075-2375 + T Sin 24.5 =0 Ay. ·-3450 + 1.61*103 x Sin 24.5 =0 => Ay z 2782-3N Aya 2.782.KN