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A restaurant owner finds that the time customers wait between sitting down and their server arriving is a random variable disConsider the situation in the previous problem. The owner wishes to post a sign saying that customers who have waited longer

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Answer #1

Ans:

P(T<=t)=1-exp(-t/2.5)

1)P(T>4)=exp(-4/2.5)=0.2019

2)

P(T>M)=0.001

exp(-M/2.5)=0.001

M=-2.5*ln(0.001)

M=17.27 minutes

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