Question

Question 5 --/5 View Policies Current Attempt in Progress Figure (a) gives the magnitude E(x) of the electric fields that have been set up by a battery along a resistive rod of length L = 9.00 mm (see Figure (b)). The vertical scale is set by Es = 5.20 x103 V/m. The rod consists of three sections of the same material but with different radii. (The schematic diagram of the figure (b) below does not indicate the different radii.) The radius of section 3 is 2.06 mm. What is the radius of (a) section 1 and (b) section 2? E (100 V/m) 6 9 3 * (mm) (a) Number Units (b) Number Units

Answer 1

length of each section is same total length a gmm= 9X10-3 m. length of each section = ( 1 = 9X10 3 _ 3x103 cm, current en each section is same ie - I Resistance = (14 f= resistivity - same for all J (same material) L = same A = area of crossection. potential difference across each section EiR electric field = 1 d = length of the section r = radius.

on electric field anis 8 div= 5.2 X103 v/m. I div = 5.2 x10? v/m Hence E = 5x | 502 x 103 v/m = 3.25 x103 vie Ez = 8x/ 5. 2) x103 /ma 5.2 x103 Ym Ez = 3x (5.2) x103 /m = 1.95 X163 v/m. 1.95 3XIS PX (1) for El and Es E Thy 3-25 x 10 2.06 mm 2.06 mm = 1.95 x 2.06 mm = 1.59 mm l = I (b) for Ez and Es 5.2010 و نيا 1.95Xlor 103 (/482) 2.06 mm r2 = 1.26 mm