Question

3. Wind load: The building shown in the figure 2 is a disaster operation center (risk category IV) in Miami, FL and located on a flat terrain. Find the design wind pressure acting on the roof and sides of the building. (it is an enclosed building, exposure category C and the Gust effect coefficient G is 0.85). [30 points] Frame-2 plan 30 Wind direction - -- -- 30 Elevation of Frame! TIT Figure 2. Cross section and plane view of the disaster operation center.

Answer 1

ANSWER:

DISASTER OPERATIONS : Disaster operations. Activities undertaken before, during or after an event happens to help reduce loss of human life, illness or injury to humans, property loss or damage, or damage to the environment, including, for example, activities to mitigate the adverse effects of an event. Disaster Recovery Operations.
Given that wind. 30ft the slope of roof ostan! ( 160 ) = tant (0.55) 0 - 28.89 mean roof height, h= 30 +11 / = 30+ 5.5 - 35.557. h = 35.5ft

35.5 [ 0.8875 "The basic wind speed in Los Angeles is, v= 120 mph. from the table. ,. exposure categortes cc) for buildings for wind load. . zq = 900.ft, &=95 velocity exposure coefficient Kne 2011 ( 22 ) * = 2:01 ( 35,5.)/45 = 2:01 (3515) 0.210 = 2.0110.03908)0914 = 2.0160.039)0.210 = 10176 . The velocity pressure % = 0.00256 kn 4 kve 50.00256 (1.0176)(0)60(12014

= 0.00256x 10176x14400 .3 37.01 Pof for 0 = 28.8° and b = 0.8875, the values of external coefficients for leeward, cp = -0.6. given gust factor is = 0.85 @ lor cp = -0.22 bor windward side external wind pressure, Ph =qh GCp. P = (37:51) (0.55)(-0-22). -.701486 (b) for ap=0.2 Phe 37.51 (0.85 (0:2) . .-6.376 psf for leward side. Pn = q GCp = 37.51601805) (-0.6) = -19-13 pot.

6.376 psf . -19:13 psf. 1165 -7. Olupsf) 3oft