Ans) We know, velocity pressure coefficient (q),
q = 0.00256 Kz Kzl Kd V2 I
where, Kz = height factor = 0.90 for 20 ft wall (given)
Kzl = topographical factor = 1 (given)
Kd = wind directional factor = 1 (given)
V = Wind velocity = 105 miles/hr
I = Importance factor = 1 for ordinary buildings
Putting values,
q = 0.00256 (0.90)(1)(1)(105)2
=> q = 25.4 psf
Now,
External wind pressure on windward wall, Pe = q G Cp
where, Cp is external wall pressure coefficient = 0.80 for windward wall
=> Pe = 25.4 x 0.85 x 0.80 = 17.27 psf
External wind pressure on leeward side , P'e = q G Cp
To determine Cp for leeward wall , find L and B
L = Length of building = 60 ft
B = Width = 20 ft
For L / B = 60/20 = 3 and exposure B ,Cp = -0.50
=> P'e = 25.4 x 0.85 x (-0.5) = -10.8 psf
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