Question

5. (15 points) Calculate Z, HR and SR for carbon dioxide at 325 K and 60 bar by the Lee-Kesler correlations.

Answer 1

Solution- @ Calculation of 'z' whore I- 35k p = Gobar from table of characteristics Propeuties of puse Species- for Carbon dioxide W = 0.224 Te = 304.2K Pc = 73.83 bar Now To = I = 325 1.068 - To 3042 Pp EI = 60 = 0.8126 PC 73-83 from table of values of Zo At Pr = 0.8/26 2 0 - To = 1.0689 zº = 0.7132 also Pre0.8126 y = -0.0033 - Tor - 1.068 L Now, z=20+ wzl z = 0.7132 H_-224 X-0.0033 Z=0.7132 +_7.392 X164] Z=0.7124

6 from table of values of HEHR I RTC RTC at Py = 0.8126 2 (HR) - Tr=1.068 ERIC - 0.958 at Pr = 0.81262 (HR) To - 1.068 RTE Now, = -0.958 +(0.224*-0.694) RTC HR - 11134 HR-1.1134 x 8-314x 304.2 LRT = -2816.06 Jm @ from table of values of - Geoff we get 6 ce at Po=0.8126 To 1.068 -0.659 RS - b SR T'=0.645 se af syt we G =-0.659 +0-224 X-0.645) SM -0.8034 Sk -0.8034*8: 3/4 gh - - 6. 680 J/molk