let h is the height above the surface of the earth the geostationary satellite revolves.
we know, Me = 5.97*10^24 kg
Re = 6.37*10^6 m
let h is the height of geostationary satellite.
The time period of geostationary satellite, T = 24 hours
= 24*60*60 s
= 86400 s
we know, T = 2*pi*(Re + h)^(3/2)/sqrt(G*Me)
T^2 = 4*pi^2*(Re + h)^3/(G*Me)
G*Me*T^2/(4*pi^2) = (Re + h)^3
==> Re + h = ( G*Me*T^2/(4*pi^2) )^(1/3)
==> h = ( G*Me*T^2/(4*pi^2) )^(1/3) - Re
= ( 6.67*10^-11*5.97*10^24*86400^2/(4*pi^2))^(1/3) - 6.37*10^6
= 3.59*10^7 m <<<<<<<--------------------Answer
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