Question

Required Information Euler's buckling formula can be expressed as Po (RE) where P is the critical buckling load, Eis the column's Young's modulus, is the column's moment of Inertia, and L is the column's length. Derived using a quantity called effective length, the constant K depends upon the column's end conditions This problem will compare various end conditions of a slender column under compression. The studied column has a length of 2 - 1 meters, and its square cross-section has a side length of b = 4 centimeters. The material is a grade of steel with E-200 GPa and Oy - 500 MPa. What is the fixed-pinned column's critical buckling load in megaNewtons (MN)? [You must provide an answer before moving to the next The fored-pinned column's critical buckling load is determined to be 0.841 OMN.

Answer 1

soln (KL) 2 Buklly load Per = TREI -0. € = 200lapa = 2ooxcolpa , b= 4cm I= bxb2 - 4 = 2133 cm = 2.33 X60-6m?* L=1m. k=1/4 Now using for fixed - pinned colouna 0 Per = 7 x 200x/0 x 21:33 X108 (1 x 12. Per = 842208. 24 N. Por = 0.842 MN.