Question

Given the following block of material, which has a permittivity, and conductivity, o, compute the capacitance and resistance using the various methods below for each pair of electrode surfaces Methods to use a) find C by assuming 'Q" b) find C via Poisson's Eq c) find R by assuming 'I d) find R via Poisson's Eq (use results from b) The pairs of electrode surfaces are 2) r- a and r b 3) the two rectangular faces (b-a) h There should be 4 calculations (2 for Cand 2 for R) for each pair of electrodes.

Answer 1

We'll start by listing the formulae for resistance and capacitance R = L/sigma A, C = elementof A/d z = 0, z = h this orientation has uniform cross section, so, this must be pretty straight forward of cross section A = pi (b^2 - a^2)/4 This can be derived from simple geometry and length between electrons is of courses l = d = h = uh/sigma pi (b^2 - a^2), c = sigma pi (b^2 - a^2)/4h (The second part include, the integration it's both to kook at the simpler one first then more on to the difficult one) \r\n Two rectangular faces (b - a) * h From the fig, one electrons face as attached to the y - z plane and other to the x - z plane It is observes that the two has a uniform crossection area of A = (b - a) * h Method - 1 l = d = 2 pi a + b/2/4 = pi (a + b)/4 The curve