Question

Find a point-normal equation of the plane passing through points A(1,-1,0), B(0, 0, 2) and C(0,3,1).

Answer 1

olohon Giren, A(1,-1,0), B(0, 0, 2) and CC, 3, 1) ☆ We find the ecuation by forming them in necha forum 18.a). (6-2) Ce-a ) ) = 0 - 0 As plane passes through the points a Bande hence, a = oitoj + 2K - it: = i tiita Now the cross product of (6-2) x (2-a) * (118){ -;(1119) Á (4+1) . -7 -7.3K

x = xiлу; 2, (1-3) [t) х (г.) To (кі елі 2 - 1 1 -11 - - 1 ) о [ (x-1) { + (чиј 11 11 (-1; - %) о (2-1) (-1) (чи) (-) : (x) (3) со -11+1 - - - 32 но -1х - этz , , от 1**33 - 4 го So the required equation of the plane is 32 = =o |