A one-way solid concrete slab is to be used for a simple span of 16 ft. In addition to its own weight, the slab carries a superimposed dead load of 20 psf and a live load of 90 psf. Design the slab for minimum thickness if ƒy is 40 ksi, and ƒ’c is 3 ksi
9 in
8 in
6 in
7.6 in
A one-way solid concrete slab is to be used for a simple span of 16 ft....
Example CVEG 4303: Reinforced Concrete I One-Way Slabs A 5" thick concrete slab is reinforced for tension with #4 bars spaced at 7". The effective depth is 4" Grade 60 bars and 8,ooo psi concrete will be used. 1.) Determine the design bending strength (фМп) of the slab. 2.) Check that ACI requirements for rebar strain, rebar spacing, and minimum reinforcement are met (ACI 7.3.3.1, ACI 24.3.2, and ACI 7.6.1.1 respectively). Note: Do not need to check temperature and shrinkage...
Design a 24-in.-wide precast concrete slab to support a 60-psf live load for a simple span of 15 ft. Assume the minimum concrete cover required to be 5 in. Use welded wire fabric for reinforcing steel. J.-б0,000 psi,//-3000 ps, and ρ = 0.18/ 'My (Ans. 4-in. slab with 4 × 8 D12/D6)
Design a 24-in.-wide precast concrete slab to support a 60-psf live load for a simple span of 15 ft. Assume the minimum concrete cover required to be 5...
Design interior one-way slab for the situation shown. Concrete
weight = 150 lb/ft^3
f_y= 60,000 psi, f_c= 4,000 psi.
Do not use the ACI Code’s minimum thickness for deflections.
Assume: h= 7.5 in, b= 12 in,
d= h-0.75-(0.25)
steel percentages are given on the figures.
The only dead load is the weight of the slab
WL150 psf im -24 ft
WL150 psf im -24 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy- 50 ksi 35 ft 15 ft Wu 35 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy- 50 ksi 35 ft 15 ft Wu 35 ft
Design a simple-span, one-way slab to carry a uniformly distributed live load of 375 psf plus the self-weight of the slab. The span is 10-ft., center-to-center of the supports. Assume fe' = 4,000 psi and fy = 60,000 psi. Design per foot of width. Use #5 bars for both longitudinal and temperature and shrinkage reinforcement. (30 pts.)
please solve it manually and using ETABS.
please solve it manually and using ETABS.
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy 50 ksi 35 ft 15 ft Wu 35 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy 50...
A 5 in thick simply supported
reinforced concrete one-way slab is part of a roof system. It is
supported by two masonry block walls, as shown below. Assume a
superimposed dead load (roofing, insulation, ceiling, etc.) of 15
psf and a roof live load of 30 psf. Check the adequacy of the slab,
including the required shrinkage and temperature reinforcement. Use
= 4,000 psi and = 60,000 psi.
1. A5 in thick simply supported reinforced concrete one-way slab is part...
question 9 (a)
9 Design interior one-way slabs for the situations shown. Concrete weight 150 lb/ft3, fy= 60,000 psi, and f c= 4000psi. Do not use the ACI Code's minimum thickness for deflections (Table 4.1). Steel percentages are given in the figures. The only dead load is the weight of the slab. a) WL150 psf 24 ft
Assume normal concrete weight (wc = 143 lb/ft) with specified compressive strength fc = 4,000 psi, and steel Grade 60 (fy = 60,000 psi). For design loads assume dead load wd = 30 lb/ft? (excluding self-weight) and live load we = 100 lb/ft. Finally assume that the steel percentage ratio is equal to p= 0.18fc/fy. Design an interior one-way simply supported slab with a 15 ft span using the above assumptions. Show sketches of one-way slab cross section, including reinforcing...
Problem 3 Assume normal concrete weight (wc = 143 lb/ft) with specified compressive strength fc = 4,000 psi, and steel Grade 60 (fy = 60,000 psi). For design loads assume dead load wd = 30 lb/ft? (excluding self-weight) and live load wų = 100 lb/ft. Finally assume that the steel percentage ratio is equal to p= 0.18fc'/fy. Design an interior one-way simply supported slab with a 15 ft span using the above assumptions. Show sketches of one-way slab cross section,...