Question

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A radioisotope of iodine, ¹³¹I, is used to study thyroid function. A patient is given a sample that is

1.70

×

10⁻⁴M ¹³¹I.

If the half-life is

8.04 days,

what fraction of the radioactivity remains after

29.0 days?

Radioactive decay is a first-order process.

Answer 1

hope you will like my answer

0.693 for radio-active decay. t= 2.303 log to where a= decay constant = No = initial conch N = Concentration at ty time 't t= 2.303 × ty log No 0.693 given [No] = 1070 x 10-4M ty = 8.04 days t = 29 days. log (1070x 10-4) :: 29 = 2.30 3 X 8.04 0 a 693 1070 x 10-4 - 12.172. IN = 1048 10 M L Am