Question

PLEASE ANSWER STEP BY STEP

A thrill-seeking cat with mass 4.00 kg is attached by a harness to an ideal spring of negligible mass and oscillates vertically in SHM. The amplitude is 0.050 m, and at the highest point of the motion the spring has its natural unstretched length. Calculate the elastic potential energy of the spring (take it to be zero for the unstretched spring), the kinetic energy of the cat, the gravitational potential energy of the system relative to the lowest point of the motion, and the sum of these three energies when the cat is

Part A

Calculate the elastic potential energy of the spring (take it to be zero for the unstretched spring) when the cat is at its highest point.

Uspring =	0.98	J

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Part D

Calculate the sum of these three energies when the cat is at its highest point.

E =		J

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Answer 1

Part A At the highest point, the spring is unstarched. Hence, potential energy is equal to zero. Part D: At the highest point, the velocity of the cat is equal to zero The gravitational 1 potential energy is, -mg (2A) Since h 2A) = (4.0 kg)(9.8 m/s)2(0.050 m) -3.92J Hence, the sum of the three energies is in K+PE 0+0+3.92 J -3.92J