Id: 40100885
in c++
output text please
thanks!
#include <iostream> using namespace std; int m = 0; void SampleMethod(int); int SampleMethod(); void increase(); int main() { int j=9; SampleMethod(j); cout << j <<endl; return 0; } // This function can not return any value because the return type is void void SampleMethod(int j){ if(j%2 == 1) cout << SampleMethod() << endl; //print the value return by SampleMethod() else cout << j << " "; m = m + 2; cout << m << endl; j = j+1; } // This function return the value because the return type is int int SampleMethod(){ int j=10; cout << j*3 <<endl; // it print 30 increase(); // call the increase() function return j + 3; } void increase(){ m = m + 5; }
Output :-
30
13
7
9
Explanation:-
Execution is starts from main method. In main method j =
9 then we call SampleMethod( 9 ) ;
function
In SampleMethod(int j) check if( 9 % 2 == 1 ) is true it means that
cout << SampleMethod() << endl; statement is executed
and the value return by SampleMethod() is
printed.
In SampleMethod() j = 10 ; cout << j*3 <<endl; means
30 is printed and after that
increase() function is call.
In increase() m = m + last digit of your student id ; and the
last digit of your student id = 5
because Id: 40100885 given so m =
5;
After that in SampleMethod() last statement return j + 3; is
executed , so it will return 13 to
SampleMethod(int j) and
With the help of this statement cout <<
SampleMethod() << endl; 13 is
printed.
After that In SampleMethod(int j) this statement m = m + second
digit of your student number + 2; is executed and the value
of second digit of your student number is 0 from Id:
40100885 and m = 5+2=7 and 7 is printed with the
help of cout << m << endl;
After executing the SampleMethod(j) in main method , the statement cout << j <<endl; is executed and 9 is printed.
So the output is :-
30
13
7
9
Id: 40100885 in c++ output text please thanks! what is the output values printed by the...
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