In the given reaction stoichiometric coefficient of Mg is 2. Means the given ∆H = -1203 kJ is the amount of heat released when 2 mol of Mg associated.
Now multiply the reaction by 2, then ∆Hnew = 2∆Hrxn. We get,
4Mg + 2O2 ----> 4MgO ∆Hnew = 2∆Hrxn = 2(-1203 kJ) = -2406 kJ
Now the Stoichiometric coefficient of Mg is 4. Means now 4 mol of Mg is associated and when 4 mol.of Mg is associated ∆H is -2406 kJ. Hence, ∆H = -2406 kJ.
Option E (Last option) is correct answer.
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=-1203 kJ Consider the following reaction:2 Mg +02 -2 Mg0 AH rxn Calculate the amount of...
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