Question

In Java, write a recursive method that converts an integer to hexadecimal. The function should print out the hexadecimal character instead of returning the character. Write a test program that prompts the user to enter an integer and displays its hexadecimal equivalent.

Answer 1

import java.util.Scanner;

class Main {
public static void convertToHexa(int n)
{
// If number is greater than 15 then calling it recursively with n/16
if(n>15)
convertToHexa(n/16);
  
// printing Hexadecimal numbers which is reminder
if(n%16 == 10)
System.out.print("A");
else if(n%16 == 11)
System.out.print("B");
else if(n%16 == 12)
System.out.print("C");
else if(n%16 == 13)
System.out.print("D");
else if(n%16 == 14)
System.out.print("E");
else if(n%16 == 15)
System.out.print("F");
else
System.out.print(n%16+"");
}
public static void main(String[] args) {
  
// declaring scanner
Scanner sc = new Scanner(System.in);

// taking user input
System.out.print("Enter an integer: ");
int num = sc.nextInt();

// printing output
System.out.print("Hexadecimal: ");
convertToHexa(num);
}
}

/*SAMPLE OUTPUT
Enter an integer: 23451
Hexadecimal: 5B9B
*/