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A 0.2-kg spool slides down along a smooth rod. If the roc has a Part A constant angular rate of rotation = 2rad/s in the vert

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(0-2)19.2161.962 N Given i = a radls and öo Ave = vë-vo²=vi-ve(2)² = vi-ave No = ve ö + Qui Ò = 0 + Qui(2) = 4u2 Consider FBDLAt t=0, Vi=0 eq@ 03-261 +262-98 0 = +262 +262 -9.81 C1=-623-7181 1913-9780) Thus v=-9.81 et 2.81 et 9.8 sinat =9.81 (-4204e2

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