Question

The tires on a new compact car have a diameter of 2.0 ft and are warranted...

The tires on a new compact car have a diameter of 2.0 ft and are warranted for 57,000 miles.

(a) Determine the angle (in radians) through which one of these tires will rotate during the warranty period. rad

(b) How many revolutions of the tire are equivalent to your answer in (a)? rev

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Answer #1

(a) Distance, L = r Phi

where L is the miles that is given under warranty period.

r is the radius of the car tire,

Phi is the angle that is equivalent to cover the distance L.

Hence,

(57000 miles) (diameter)/2 2 ft)/2 (57000 miles) x (5280 ft/miles) (1 ft) 300960000 radians-3.01 108 radians

(b) The angle covered by the tire is going to get repeated once it completes the 2pi radians.

Hence, if we have to give this angle within this value, we can rewrite the total angle as the sum of the integral multiples of the 2pi and the residual angle, Phi_0 .

Phi=(2pi n)+Phi_0

where n is the number of revolutions made by the car within the warranty period.

By substituting the total angle into the above formula, we can observe that,

Φ 300960000 radians-12t(47880000) + 01 radians

Hence, the tire will have to finish 47.88 M (47.88 x 106)revolutions in order to cover the warranted miles.

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