Question

A)

What is the overall order of reaction for a reaction that obeys the rate law rate k[A]²[B]³

b)

c)

Answer 1

a) from the knowledge of chemical kinetics

in the expression of rate law, the numbers in the exponent of any concentration term is called the order of reaction with respect to this particular concentration term.

say for any reaction a rate law is expressed as,

$rate=K\left [ A \right ]^{\alpha }\left [ B\right ]^{\beta }$

here clearly 'alpha' is the order of the reaction w.r.t A and 'beta' order of the reaction w.r.t B.

now overall order of the reaction expressed as, $order=(alpha+beta)$

so, for our case,

$rate=K\left [ A \right ]^{\2}\left [ B\right ]^{\3 }$

now overall order of the reaction = (2+3) = 5

b)

say the rate equation is,

$rate=K\left [ A\right ]^{\alpha}\left [ B\right ]^{\beta}$

$rate(1)=K\left [ 1*10^{-2}\right ]^{\alpha}\left [ 1.0\right ]^{\beta}=0.3*10^{-6}$ ...1

$rate(2)=K\left [ 1*10^{-2}\right ]^{\alpha}\left [ 3.0\right ]^{\beta}=8.1*10^{-6}$ ....2

$rate(3)=K\left [ 2*10^{-2}\right ]^{\alpha}\left [ 3.0\right ]^{\beta}=3.24*10^{-5}$ ....3

now, dividind (2) by (1)

$\left [ 3.0\right ]^{\beta}=27$

$\left [ 3.0\right ]^{\beta}=3^{3}$

$\beta =3$

dividing (3) by (2)

$\left [ 2\right ]^{\alpha}=4$

$\left [ 2\right ]^{\alpha}=2^{2}$

$\alpha =2$

so, the order of reaction w.r.t A =2

so, the order of reaction w.r.t  B =2

overall order of the reaction=(2+3) =5

C)

if for every 10⁰ C increase of temperature, the rate becomes double of the initial then for 40⁰C increase of temperature the rate will be (2)⁴ = 16 times of the initial.

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