Question

Math 122B Homework 12 (Sections 5.4 and 6.1) Due Tuesday, April 28. Homework 12 (Sections God and 0.1) Dwo Tuesday, April 26 (d=7, Snyde = 13, [n()dt = -5. 1. Suppose (a) Find h(t)dt. (b) Find 13h(t)dt. (e) Find $2h(t) – 1]dt.

Answer 1

I am attaching the pictures of solution. If you find my answer helpful please press thumbs up button. Thanks

Ang (hld)dt = 7-O ssh(t)dt = 13 - I n (a) da = -5- (a) S & M (H) dit = f'nodd + hlasda + LulAsd a [by property of definite integral it alblccd then cd cb then I hende = Searca su + Svinek + [wansda 6&dt=ht) ht att hladt Here a=-1, b=1, C=5, d= 6 l

h(*) dt = 7+13-5 - 20-5=15 using and , ③ & I - [ n(t) dx = [15]

5 3 b (+) dx = 35 % baldt [èncu)dt = cc of Da ne here c= constant , n(A)dt = 3 Shusdt = 36-5) (using ] Sh()dt = Fis (o s 2 h (A) - 1) dx = 5 2 h (A) dt - Sat F = 259 n(A) det - gat [as se nude = c Sint!d = 2 (13) – [+] 15 (as S&t= x] C - 26-[5-1)

وو = و - ، و = ه - ر) ط رد 33 = 4 (1- (4) دور و