Here ,
m = 0.065 Kg
k = 40 N/m
A = 0.05 m
a) total energy of the system = 0.50 * k * A^2
total energy of the system = 0.50 * 40 * 0.05^2
total energy of the system = 0.05 J = 50 mJ
total energy of the system is 50 mJ
b) let the speed is v
Using conservation of energy
0.50 * 0.065 * v^2 + 0.50 * 40 * 0.011^2 = 0.05
solving for v
v = 1.21 m/s
the speed of the object is 1.21 m/s
c)
kinetic energy = 0.05 - 0.50 * 40 * 0.025^2
kinetic energy = 0.0375 J = 37.5 mJ
kinetic energy is 37.5 mJ
d)
potential energy = 50 - 37.5
potential energy = 12.5 mJ
A 65.0-g object connected to a spring with a force constant of 40.0 N/m oscillates with...
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