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The number of claims for lost luggage in a small city airport averages 7 per day....

The number of claims for lost luggage in a small city airport averages 7 per day. Assuming the Poisson distribution, what is the probability that there will be 5 or fewer claims on any given day?

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Answer #1

Xu Poiss (x) PMF of x is PCX =)) = pe 26= 0,1,2,---- C! Here, x= we have to find us P( x < 5) = PCX-X) =e7[+ 7 + 7 +7 + -10.3

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