Question

15. Hypothesis Test for Heights of Supermodels The heights are measured for the simple random sample of supermodels Crawford,
movie April BMI September BMI 20.15 19.24 20.77 23.85 21.32 20.68 19.48 19.59 24.57 20.96 10. Confidence interval for BMI Cha
1 0
Add a comment Improve this question Transcribed image text
Answer #1

15.)

Supermodele not Supermodels. 48.15) n = 9 n2= X2 40 63.2 S2 = 2.7 2 To si d=0.01 To test Hoi li lli - lz & Hillilla Test Stat

Conclusion: Since we reject Ho, there is sufficient evidence to support the claim that mean height of supermodels is greater than mean height of women who are not supermodel.

10.)

(8.10) Let us : Mapril - ll sept April BMI September BMI Defforense di -0.53 20.15 19:24 -0.24 : 20.77 23.85 21.32 20.68 19:4

The confidence interval includes 0. This we accept Ho and can say that BMI has not changed during the freshman year.

Add a comment
Know the answer?
Add Answer to:
15. Hypothesis Test for Heights of Supermodels The heights are measured for the simple random sample...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 5. Listed below are the body mass indices (BMI) of a sample of freshmen. The BMI...

    5. Listed below are the body mass indices (BMI) of a sample of freshmen. The BMI of each student was measured in September and April of the freshman year. April BMI 20.15 19.24 20.77 23.85 21.32 September BMI 20.68 19.48 19.59 24.57 20.96 At a 0.05 significance level, does BMI appear to change during freshman year?

  • #19. The sample heights collected randomly from nine supermodels have the mean of 70.0 in, and...

    #19. The sample heights collected randomly from nine supermodels have the mean of 70.0 in, and the standard deviation of 1.5 in. Another sample set randomly collected from 40 non- supermodels shows the mean of 63.2 in. and the standard deviation of 2.7 in. Assume that we are using 0.05 significance level to test the claim that the mean height of the supermodels is greater than that of non-supermodels. Also assume that two groups of samples are independer and Determine...

  • 3.Heights of Supermodels. List below are heights(cm) for the simple random sample of 16female supermodels. Use...

    3.Heights of Supermodels. List below are heights(cm) for the simple random sample of 16female supermodels. Use a 0.01significance level to test the claim that supermodels have heights with a mean that is greater than the mean height of 162 em for women in the general population. Given that there are only 16 heights represented. can we really conclude that supermodels are taller than the typical women? 178 177 176 174 175 178 175 178 178 179 180 176 180 178...

  • 1.      The heights are measured for supermodels Niki Taylor, Nadia Avermann, Claudia Schiffer, Elle Macpherson, Christy Turlington,...

    1.      The heights are measured for supermodels Niki Taylor, Nadia Avermann, Claudia Schiffer, Elle Macpherson, Christy Turlington, Bridget Hall, Kate Moss, Valeria Mazza, Kristy Hume and seven other supermodels. They have a mean of 70.2 inches and a standard deviation of 1.5 inches. Use a 0.01 significance level to test the claim that supermodels have heights with a mean that is greater than the mean of 63.6 inches for women from the general population. 2.      A recent Gallup poll of 976 randomly...

  • A simple random sample of 16 supermodels' heights (in centimeters) was taken. 178, 177, 176, 174,...

    A simple random sample of 16 supermodels' heights (in centimeters) was taken. 178, 177, 176, 174, 175, 178, 175, 178, 178, 177, 190, 176, 180, 178, 180, 176 a) use a .05 significance level to test the claim that supermodels have a mean height greater than the population of women, whose mean is 162 cm. b) Given that there are only 16 values in the sample, are your conditions from part a valid? Why or why not? c) Construct a...

  • 8. Listed below are the heights (inches) for the simple random sample of supermodels. Use a...

    8. Listed below are the heights (inches) for the simple random sample of supermodels. Use a 0.05 significance level to test the claim that supermodels have heights with a mean that is greater than the mean height of 63.8 in. for women in the general population. Do not use the p-value. 70 71 69.25 68.5 69 70 71 70 70 69.5

  • Need help with these problems A researcher collected a simple random sample of the cents portions...

    Need help with these problems A researcher collected a simple random sample of the cents portions from 100 checks and from 100 credit card charges. The cents portions of the checks have a mean of 23.8 cents and a standard deviation of 32.0 cents. The cents portions of the credit charges have a mean of 47.6 cents and a standard deviation of 33.5 cents. Construct a 95% confidence interval for the mean difference between the cent portions of credit cards...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT