Question

Problem 1.1: Using dimensional equations convert 500 m^/(day.kg) to cm^/(s.g). Problem 1.2: You have given: u = Uo+gt; Here u = m/s, uo = ft/min, g = m/s2, t=hr Is the equation valid? Convert it to dimensionally homogeneous and consistent equation. Problem 1.3: Calculate the weight in dynes of a 5 ton object (1 ton = 2000 lbm). Express the result in scientific notation having 3 significant numbers.

Answer 1

x = Soom day .ng Now on Im = I day = 1 kg = 10² on (24 x 60 x 60) 103 g to see see " x = 500 x (10²) cm (24 x 60x60) x103 s. 578.7037 (1.2) u = A = Up B & gt + c We need to convert wits of term B and C to writs of → B - = = It Imin x 0.30u8 4 I L 60 ft = I min = 7 0.3048 in 60 sec = qt x 3000 mxs [ Ihr = 36005] Thus, equation modifies u = 10 x 0.3048 to : + 3600 gt 50 3600 gt This equation is valida

Date - Mass = = = = 5 ton 5 x 2000 ton I Iton = 2000 ton 5 * 2000 * 0.453592 kg [ I lom - 0.453542 Kg 4535, 42 - weight ma = 4535.92 x - where = 9.81 mis² 9.81 kgm = 44497. 3752 N = 44497. 3752 x 105 dynes LS [ 1 kgm [ IN = 10 = 105 dyres ] 4449737520 = 404497 x 109 dynes