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AS FOR GIVEN DATA...
S0LUTION ::-
To test whether there is any significant difference between the two conditions we can perform chi-squared test.
To test we can use R codes.
CODE:
x <- matrix(c(48,23,14,9),nrow=2)
chisq.test(x)
OUTPUT:
> x <- matrix(c(48,23,14,9),nrow=2)
> chisq.test(x)
Pearson's Chi-squared test with Yates'
continuity correction
data: x
X-squared = 0.11515, df = 1, p-value =
0.7344
NOTE ::- Here the P-value of the test is greater than 0.05. So, at 5% level of significance. we don't have enough evidence to say there is no relation between the two conditions. So, there is a significant difference between the two conditions.
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