expanding above :M(t) =(1/36)*e-6t +(25/36)e4t +(10/36)e-t
therefore
P(X=-6)=1/36
P(X=-1) =10/36
P(X=4)=25/36
P(X>-3|X<2) =P(-3<X<2)/P(X<2) =(10/36)/(11/36)=10/11 =0.91
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