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You need 100.00 mL of a buffer at pH 10.50 based on carbonate (H2CO3; ka1 =...

You need 100.00 mL of a buffer at pH 10.50 based on carbonate (H2CO3; ka1 = 4.3 x 10^-7, ka2 = 5.6 x 10^-11). you have available the following materials: solid sodium bicarbonate (84.006 g/mol), 2.000 M HCl, and 2.000 M NaOH and of course di water. To ensure adequate buffering capacity, the buffer component present at lower concentration should be at 0.200 M. provide a recipie indicating volumes of liquids and/or masses of solids for technician to use in making this buffer. The awnser is 18mL NaOH + 4.7 g NaHCO3 + water. How do you get it?

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Answer #1

Coz H-Cわ3 Co 7 Acid p7 esent n lower cenc han the boaR Giiven thet th Lower con componant a o 2o M , ラ . e = 0.302서 けco ) LC

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