You create a 1 L solution of 0.1 M H2CO3. carbonic acid, H2CO3,
is a diprotic acid with Ka1 = 4.5 x 10-7 and Ka2 = 4.7 x
10-11.
a) What will the initial pH of the solution be?
b) What volume of 0.1 M NaOH will you need to add to reach the
second equivalence point( remember carbonic acid deprotonates to
bicarbonate HCO3- and then can deprotonate further to CO32-?
c) At the second equivalence point, what will the pH of the
solution be?
You create a 1 L solution of 0.1 M H2CO3. carbonic acid, H2CO3, is a diprotic...
What is the pH of a 0.10 M solution of carbonic acid? Carbonic acid, H2CO3 has two acidic protons: H2CO3 + H2O7 HCO3 + H30+ Ka1 = 4.3x10-7 HCO3 + H202 CO32- + H30+ Ka2 = 5.6x10-11 a) 1.00 b) 0.70 c) 6.37 d) 3.68 e) I still can't figure this out...
Carbonic acid, H2CO3 is a diprotic acid with Ka1 = 4.3 x 10-7 and Ka2 = 5.6 x 10-11. What is the pH of a 0.47 M solution of carbonic acid?
a) Find the concentration of H+, HCO3- and CO32-, in a 0.01M solution of carbonic acid if the pH of this is 4.18. Ka1 (H2CO3) =4.45 x 10–7 and Ka2 =4.69 x 10–11 (b) Calculate the pH at the equivalence point of the titration between 0.1M CH3COOH (25 ml) with 0.05 M NaOH. Ka (CH3COOH) = 1.8 x 10–5.
Determine the pH of a 0.18 M H2CO3 solution. Carbonic acid is a diprotic acid whose Ka1 = 4.3 ×10-7 and Ka2 = 5.6 × 10-11.10)A) 10.44 B) 5.50 C) 4.31 D) 11.00 E) 3.56
Use the following chemical reaction a 6.8X1l0^-3 solution of carbonic acid: H2CO3 (aq) +H2O (l) <-> HCO3 (aq) + H3O . Ka1= 4.3x10^-7 . Ka2= 4.7x10^-11 a. if you add NaHCO3 to the solution, would the pH of the solution go up, down, or stay the same? b. Calculate the pH of the solution if you added 3.4 x10^-3 M NaHCO3.
In waters affected by acid rain the concentrations of the three carbonic acid species (H2CO3, HCO3-, CO32-) are determined by concentration of the strong acid deposited by acid rain, as well as the concentration of H2CO3 which is controlled by the solubility of carbon dioxide . Under these conditions (constant H2CO3 and relatively low pH) the only carbonic acid equilbrium of importance is the conjugate base reaction of HCO3-, which is related to, but not identical to - and not...
Find the pH of a 0.100 M carbonic acid (H2CO3) solution. Find the equilibrium concentration of CO3 -2. Ka1 = 4.30 x 10-7 Ka2 = 5.59 x 10-11
1) Consider a 0.040 M solution of carbonic acid. Calculate the pH of this solution as well as the equilibrium concentrations of: [H2CO3], [HCO3-], [H3O+], and [CO32-). H2CO3 + H20 5 HCO3 + H30+ K1 = 4.45 x 10-7 HCO3 + H20 5 CO32- + H30+ K2 = 4.69 x 10-11
The next three (3) problems deal with the titration of 431 mL of 0.501 M carbonic acid (H2CO3) (Ka1 = 4.3 x 10-7, Ka2 = 5.6 x 10-11) with 1.7 M KOH. What is the pH of the solution at the 2nd equivalence point? What will the pH of the solution be when 0.2045 L of 1.7 M KOH are added to the 431 mL of 0.501 M carbonic acid? How many mL of the 1.7 M KOH are needed...
Titration of a diprotic acid with a strong base You have a 10.0 mL solution containing 0.5 M carbonic acid. Carbonic acid is diprotic, with pKa1 = 6.35 and pKa2 = 10.33. You titrate this solution using 1.00 M NaOH . (a) Calculate the pH of the solution before adding any NaOH. (b) Calculate the amount of NaOH needed to reach the first midpoint. What is the pH? (c) Calculate the amount of NaOH needed to reach the first equivalence...