Question

7. A hypereutectoid steel contains 0.8% C. When slow cooled from austenite the following transformation products result. a) ferrite and bainite b) ferrite and martensite c) ferrite and pearlite d) pearlite and cementite 8. Pearlite is a combination of a) cementite and iron carbide b) ferrite and cementite c) ferrite and bainite d) ferrite and martensite 9. The process of hardening steel consists of what two steps? a) melting the steel followed by quenching b) melting the steel followed by slow cooling c) austenitizing the steel followed by quenching d) austenitizing the steel followed by slow cooling 10. Austenite is held above the upper critical temperature for a set amount of time for what purpose? a) it results in a uniform lattice structure b) the amount of carbon and alloying elements become uniform throughout c) to assure that all parts in the load completely transform to austenite d) all of the above 11. Austenite transformation products depend on the following: a) carbon level only b) time only c) severity of quench only d) none of the above 12. The nose of the time-temperature-transformation (T-T-T) diagram can be pushed out to an increased time by: a) increasing the severity of the quench b) decreasing the severity of the quench c) increasing the percent carbon d) decreasing the percent carbon

Answer 1

d) ρ eax1ite and cementite ferrite amd Cementite. () dus temi tizing 4he stcel solletbs gkenchiyr. ) 411 o the above D b time only (d) decrasing the perent car bor.