Below is a table of results of E. coli grown in in nutrient broth (NB) and minimal medium (MM) over 220 min.
Time (min) | A600 of | |
NB | MM | |
0 | 0.044 | 0.038 |
20 | 0.177 | 0.074 |
40 | 0.321 | 0.116 |
60 | 0.429 | 0.167 |
80 | 0.523 | 0.235 |
100 | 0.638 | 0.285 |
120 | 0.849 | 0.300 |
140 | 0.925 | 0.367 |
160 | 1.101 | 0.428 |
180 | 1.159 | 0.468 |
200 | 1.198 | 0.471 |
220 | 1.209 | 0.488 |
Using the above data, plot absorbance (log scale) versus time (linear), drawing both conditions on one set of axes.
Upload the graph as a jpg file to this assignment (an Excel graph or a photo of a manually drawn graph is acceptable).
Label your graph appropriately.
Remember, you will not get any marks if your semi-log graph is titled as "Absorbance versus time" because this is already the label of your Y and X axes.
Determine the growth rate constant for E. coli growing for each culture media. Show your calculations in the space below.
Blue- culture media 1, orange - culture media 2
culture media 1
growth rate constant (µ) = ( (log10 N - log10 N0) 2.303) / (t - t0)
= (0.321- 0.044) 2.303 /40 min
= 0.01594 min-1
culture media 2
growth rate constant (µ) = ( (log10 N - log10 N0) 2.303) / (t - t0)
= (0.523- 0.038) 2.303 /80 min
= 0.01396 min-1
Below is a table of results of E. coli grown in in nutrient broth (NB) and...