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LILID DIISID, LLUN IDA OCTOBER 26, 2018 Make an educated guess as...
please help me solve within 30 min Question 5 On October 26, 2009, President Obama had...
please help me solve within 30 min
Question 5 On October 26, 2009, President Obama had an approval rating of 44% (accordi Gallup Poll). Suppose a sample of 100 Americans is taken that same week. What probability that the sample proportion has between a 40% and a 45% approvals 4 or more decimal places in your computations! 2961 7291 2117 0228 8438 3703
Please help me find the answers to the last two problems step by step. The average...
Please help me find the answers to
the last two problems step by step.
The average playing time of compact discs in a large collection is 35 minutes, and the standard deviation is 5 minutes. (a) What value is 1 standard deviation above the mean? 1 standard deviation below the mean? What values are 2 standard deviations away from the mean? 1 standard deviation above the mean 1 standard deviation below the mean 30 2 standard deviations above the mean...
Data of BMI: 25 25 26 27 28 30 30 31 32 35 35 38 10)...
Data of BMI: 25 25 26 27 28 30 30 31 32 35 35 38 10) Calculate the standard deviation, variance, and the z-score of someone with a BMI at 21. 11) Is this z-score unusually high or low? (If yes, specify which one). 12) Identify the 5-number summary below 13) Calculate the IQR 14) Identify any outliers 15) Draw a boxplot of your data (modified for outliers) 16) Write a sentence describing the shape of the distribution (skewed or...
Please show me how to do it on TI84 or show work. Test the claim that...
Please show me how to do it on
TI84 or show work.
Test the claim that the mean GPA of Orange Coast students is significantly different than the mean GPA of Coastline students at the 0.1 significance level. The null and alternative hypothesis would be The test is: left-tailed right-tailed two-tailed The sample consisted of 45 Orange Coast students, with a sample mean GPA of 2.77 and a standard deviation of 0.07, and 45 Coastline students, with a sample mean...
Age, Deviation, Squared Deviation, Frequency, Frequency x Squared Deviation EXERCISE #2 You fill in the 3rd...
Age, Deviation, Squared Deviation, Frequency, Frequency x
Squared Deviation
EXERCISE #2 You fill in the 3rd column of this table. The first entry is done for you. Commas are not necessary. Frequency Table for Data Set B Age (years) Frequency Age x Frequency 18 19 20 21 1782 105 45 31 12 28 10 15 16 1995 900 651 23 24 25 26 27 28 29 30 31 35 644 2 40 3 75 416 2 16 280 2 32...
For the follwoing date find: 31 20 32 18 53 53 61 | 27 | 34...
For the follwoing date find: 31 20 32 18 53 53 61 | 27 | 34 20 22 49 26 48 20 31 21 27 17 16 2018 | 24 | 36 | 20 | 20 1. The Mean= 2. The Median= 3. The Mode 4. The Range = 5. The Standard Deviation is = 6. Qı= 7. Q3=1 8. IQR= 9. Upper Fence= 10.Lower Fencer 11. If you graphed the data above, what shape would you expect the data...
Give me exact rounded answer and please give me the right answer. Lately, I've been getting...
Give me exact rounded answer and please give me
the right answer. Lately, I've been getting false answers!
Section two is from a different question but asking the
same thing from this question
a. The best point estimate is 144.89 lb. (Type an integer or a decimal.) b. The 90% confidence interval estimate is 136.75 lb<< 153.03 lb. (Round to two decimal places as needed.) Using the simple random sample of weights of women from a data set, we obtain...
Please help with the following, I have already done most of them. Please verify Question1 Select...
Please help with the following, I have already done most of
them. Please verify
Question1 Select one answer The histogram below displays the distribution of so ages at death due to trauma (unnatural accidents and homicides) that were observed in a certain hospital during a week. opoints 18 16 14 12 10 а» 10 20 30 40 50 60 70 80 90 Age Which of the following are the appropriate numerical measures to describe the center and spread of the...
I just want to make sure these answers are right. In 2018, as a way of...
I just want to make sure these answers are right. In 2018, as a way of commemorating the 10-year anniversary of the release of the first smartphone, an undergraduate student polled a random sample of 26 her peers in hopes of estimating the average time (in hours) such students spend on their smartphone each day, on average. Using the data she collected, she produced a 95% confidence interval for the true mean time college students spend on their phone each...
can someone help me answer these please! i am stuck and these are the only questions...
can someone help me answer these please! i am stuck and these
are the only questions i do not get it would be a huge help
please
Question Help Assume that thermometer readings are normally distributed with a mean of oC and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Calsius degrees.) Between 0.75 and 1.75 Click...
please help me solve within 30 min
Question 5 On October 26, 2009, President Obama had an approval rating of 44% (accordi Gallup Poll). Suppose a sample of 100 Americans is taken that same week. What probability that the sample proportion has between a 40% and a 45% approvals 4 or more decimal places in your computations! 2961 7291 2117 0228 8438 3703
Please help me find the answers to
the last two problems step by step.
The average playing time of compact discs in a large collection is 35 minutes, and the standard deviation is 5 minutes. (a) What value is 1 standard deviation above the mean? 1 standard deviation below the mean? What values are 2 standard deviations away from the mean? 1 standard deviation above the mean 1 standard deviation below the mean 30 2 standard deviations above the mean...
Please show me how to do it on
TI84 or show work.
Test the claim that the mean GPA of Orange Coast students is significantly different than the mean GPA of Coastline students at the 0.1 significance level. The null and alternative hypothesis would be The test is: left-tailed right-tailed two-tailed The sample consisted of 45 Orange Coast students, with a sample mean GPA of 2.77 and a standard deviation of 0.07, and 45 Coastline students, with a sample mean...
Age, Deviation, Squared Deviation, Frequency, Frequency x
Squared Deviation
EXERCISE #2 You fill in the 3rd column of this table. The first entry is done for you. Commas are not necessary. Frequency Table for Data Set B Age (years) Frequency Age x Frequency 18 19 20 21 1782 105 45 31 12 28 10 15 16 1995 900 651 23 24 25 26 27 28 29 30 31 35 644 2 40 3 75 416 2 16 280 2 32...
For the follwoing date find: 31 20 32 18 53 53 61 | 27 | 34 20 22 49 26 48 20 31 21 27 17 16 2018 | 24 | 36 | 20 | 20 1. The Mean= 2. The Median= 3. The Mode 4. The Range = 5. The Standard Deviation is = 6. Qı= 7. Q3=1 8. IQR= 9. Upper Fence= 10.Lower Fencer 11. If you graphed the data above, what shape would you expect the data...
Give me exact rounded answer and please give me
the right answer. Lately, I've been getting false answers!
Section two is from a different question but asking the
same thing from this question
a. The best point estimate is 144.89 lb. (Type an integer or a decimal.) b. The 90% confidence interval estimate is 136.75 lb<< 153.03 lb. (Round to two decimal places as needed.) Using the simple random sample of weights of women from a data set, we obtain...
Please help with the following, I have already done most of
them. Please verify
Question1 Select one answer The histogram below displays the distribution of so ages at death due to trauma (unnatural accidents and homicides) that were observed in a certain hospital during a week. opoints 18 16 14 12 10 а» 10 20 30 40 50 60 70 80 90 Age Which of the following are the appropriate numerical measures to describe the center and spread of the...
can someone help me answer these please! i am stuck and these
are the only questions i do not get it would be a huge help
please
Question Help Assume that thermometer readings are normally distributed with a mean of oC and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Calsius degrees.) Between 0.75 and 1.75 Click...
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