All aldol reactions proceed due to the formation of an enolate ion that exists due to the abstraction of the acidic alpha proton in the carbonyl compound with such a proton, stabilizing the enol form of the carbonyl compound. This enolate oxygen attacks the electrophilic carbonyl carbon on the other carbonyl molecule, forming an aldol product which will be a hydroxy carbonyl, which due to the strongly acidic/basic conditions used proceeds to dehydration to yield the chalcone product.
From this it should be noted that the reaction proceeds due to the formation and stabilization of enolate ions. All carbonyl compounds with an alpha hydrogen are constantly in equilibrium with their enol forms. This rapid interconversion, termed tautomerism is called in this case as keto-enol tautomerism. This equilibrium, unless a species stabilizes enols, shifts more towards the keto-form rather than the enol-form. Thus, aldol reactions involve consumption of the less stable species in an equilbrium. This leads to the equilibrium tipping to the right to form more enol to try and re-establish the equilbrium as per Le Chatlier's principle. However, as the minor product formed is rapidly consumed in the reaction, more and more of the ketone starts to decompose and form more of the enol, which being the suitable substrate for the reaction is continously consumed, thus propagating the reaction.
If however, any strong acid/base was not used, the rapid interconversion leads to very small quantity of the product, that will be so low that the conversion is negligible. The use of the catalyst here helps tip the equilibrium in favour of product formation by stabilizing the less stable species. Further, crystallization removes the product from water, which is also a product of the aldol condensation. This will initiate greater tendency for the equilibrium to shift towards the right as the aldol product is being constantly removed while the other product - water is left in the medium.
Thus, two principles - stablizing the minor product in an equilibrium and removal of a product from the equilibrium, sustains and completes this reaction owing to the tendency of the system to try and re-establish equilibrium under the new given conditions.
ALDOL FORMATION: The Aldol product is removed from the water by CRYSTALLIZATION + H20 H3CO OCH3
Draw the major product of the following intramolecular reaction. OCH3 1. NaOCH3 کلی۔ OCH3 C9H1205 H3CO 2. H30*
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Create OscerSketch Answer 4 Draw the major product of the following intramolecular reaction. (5 points) OCH3 1. NaOCH3 oleh LOCH3 C3H1205 H3CO 2. H30* Create OscerSketch Answer 5 Draw the major product of the following reaction that begins with a retro-aldol, followed by an intra Р N 31
Identify the electrophilic and nucleophilic carbons. Draw the B-hydroxy product of aldol condensation Draw the dehydration product of aldol condensation CHEMISTRY 204 CONDENSATION REACTIONS WORKSHEET 1. For each of the reactions below: identify electrophilic and nucleophilic carbons draw the B-hydroxy product of aldol condensation . draw the dehydration product of aldol condensation. OH, H2O heat a) CH3CH2CHCH3CH2CH OH, H2O b) CH3CH2CH CH3CH2CH2CH heat еон, H2O heat CH OH, H2O d) heat CH3CH2CH OCH3, CH3OH H, H20 CH3CCH2CH2CH2CCH3 heat CHEMISTRY 204...
1) Draw the major product of the following intramolecular reaction. 2) Draw the major product of the following reaction that begins with a retro-aldol, followed by an intramolecular aldol condensation. 3) Determine and draw the structures of compounds A and B only. Do not draw the structure of compound X. Place each structure above its letter. HINT: Both A and B are esters. 4) Draw a curved arrow mechanism for the following acid-catalyzed isomerization reaction. You must show all intermediates....
1. Draw the aldol product formed from an aldol/Claisen reaction with the given starting material(s) using OH or RO in H20 or ROH. (Hint: the product of an aldol reaction is a B-hydroxy carbonyl compound or an a,b- unsaturated carbonyl compound. The a,ß-unsaturated carbonyl will be the major product unless elimination of H2O cannot form the conjugated system.) он Но, но Н,0 НО. ОН НО. он H, H НО. НО.
Draw the organic product(s) of this intramolecular aldol condensation reaction. Consider only the formation of 5- and 6-membered rings. base Draw the organic product(s) of this intramolecular aldol condensation reaction. Consider only the formation of 5-and 6 membered rings. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. They will not be considered in the grading . Draw one structure per sketcher. Add additional sketchers...