Question

Date: 03/02/20 7. Since an instant replay system for tennis was introduced at a major toumament, men challenged 1412 referee calls, with the result that 422 of the calls were overturned. Women challenged 740 referee calls and 222 of the calls were owemumed. Use a 0.05 significance level to test the claim that men and women have equal success in challenging calls. Complete paris (a) through (c) below. a. Tost the claim using a hypothesis test. hypotheses for the hypothesis test? Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative O A HOP, SP2 H, P P3 OD. HOP, =P HP, P2 B. Hy: P - P2 Hq : P4 & P2 OE HD, 2D2 H:P, P2 oc. Ho: P1 P2 H₂ P1 P2 O F. Ho: P, P2 H: P1 = P2 Identify the test statistic (Round to two decimal places as needed.) Identy the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? _the null hypothesis. There (3) - evidence to warrant rejection of the claim that women and men have equal success in The P-value is (1) the significance level of 0.05, so (2)_ challenging calls b. Test the claim by constructing an appropriate confidence interval. The 95% confidence interval is (Round to three decimal places as needed.) What is the conclusion based on the confidence interval? Because the confidence interval limits (4) men and women have equal success in challenging calls. 0, there (5) appear to be a significant difference between the two proportions. There (6) evidence to warrant rejection of the claim that Radon the rated

Answer 1

null Hypothesis: Ho: P1-P2 alternate Hypothesis: Ha: P1-P2 0.00 0.00 for 0.05 level with two tailed test, critical value of zu 1.96 Decision rule: reject Hoit absolute value of test statistic Izl>1.96 men 422 2 = Pi=xy/n = 0.2989 P=Hz/n2 = n = 1412 m2 = estimated prop. diff =Pi-P2 = -0.0011 pooled prop p =(x4+xz)/(n4+nix)= 0.2993 women 222 0.3000 740 std error Se= (01(1-21)-(1in1+1/2) = 0.0208 test stat ze(1-2)/Se = -0.05

from above:

z =-0.05

p value =0.960

The P-value is (1) greater than _ the significance level of a = 0.05, so (2) fail to rejecte nuit hypothesis. There (3) is not significant evidence to warrant rejection of the claim that women and men have equal success in challenging calls

95% Ci =-0.042 <p1-p2 <0.040

Bocuse the contence mterval leies a contains o, mere (5) does not appear to be a significant difference between the two proportions. There (6) is not ___ovidence to warrant rejection of the claim that appear to be a significant difference between the two proportions. There (6) evidence to warrant rejection of the claim that men and women have equal success in challenging calls.