magnetic field B = u0*(N/L)*I
B = 4*(22/7)*10^(-7)*(2650/0.35)*0.385 =0.00366 T
B = 0.00366 T = 3.66*10^(-3) T
please show steps and units. What is the magnetic field strength (in T) inside an ideal...
(a) Use the Ampere's law to show that the strength of the magnetic field inside an ideal cylindrical solenoid (a coil) is given off by B = µ(0)ni where n is the revolution density (the number of revolutions per unit length of the solenoid) and i is the current through the solenoid. (3p) The current in the solenoid increases at a constant rate to a constant value I in a certain time t. (b) Draw a figure across the cross...
show your work An ideal solenoid generates a uniform magnetic field inside the solenoid. Here we place two long ideal solenoids as shown (with radii 40 mm and 20 mm, respectively). The current carried by the outer solenoid It is three times as large as the current carried by the inner solenoid I2. In order to make the magnetic field inside the inner solenoid zero, what should be the ratio of the number of turns per unit length for the...
. What are the magnitude and direction of the magnetic field inside the solenoid of 39 loops of wire in its 4.1 cm length that has a current passing through of 0.679 A?
Magnetic Field inside a Very Long Solenoid Learning Goal: To apply Ampère's law to find the magnetic field inside an infinite solenoid. In this problem we will apply Ampère's law, written ?B? (r? )?dl? =?0Iencl, to calculate the magnetic field inside a very long solenoid (only a relatively short segment of the solenoid is shown in the pictures). The segment of the solenoid shown in (Figure 1) has length L, diameter D, and n turns per unit length with each...
The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 4.0 T/s. What is the electric field strength inside the solenoid at a point (a) on the axis and (b) 2.0 cm from the axis? S 2 N N SI CCCCCCCC min 1
A solenoid 3.0 cm long consists of 14,000 loops of wire. If the magnetic field inside the solenoid is 3.0 T, what is the magnitude of the current that flows through it? Group of answer choices 5.1 A 34 A 9.3 A 2.7 A
What is the strength of the solenoid's magnetic field at its center? Please check my answer. (b) A solenoid with 500 turns, 0.10 mm long, carrying a current of 4.0 A and with a radius of .01m will have what strength magnetic field at its center? (magnetic permeability in empty space u 4Tt X 107 T -m/A) 4rx 107 (500)(4 M N B-I 0.110-3 =01Mm-0.1x (0m B 25. 133 T
The magnetic field inside of a solenoid has a magnitude of 0.3 T. The solenoid is 2 cm long made up of 300 loops of wire. 1592.35 A 0.06 A 4.77 A 15.92 A The magnetic field lines around a bar magnet go from north to south. True False
Solenoids are cylindrical coils of wire that create an internal magnetic field when carrying an electric current - see section 12.1 of the textbook. A solenoid 86.0 cm long has a radius of 3.00 cm and a winding of 1900 turns; it carries a current of 3.60 A. (a) Calculate the magnitude of the magnetic field inside the solenoid in mT. (b) Calculate the magnetic field outside the solenoid in T. (We can treat this as an ideal solenoid, since...
Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tightly wound with a single layer of 1.50-mm-diameter superconducting wire. Part A What current is needed? Express your answer with the appropriate units.