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Pi- Consider two thermodynamic states 1 and 2. If —- = 2 P2 and- = 2...
02) Consider a hydrostatic system represented by the thermodynamic variables volume V, pressure P and temperature...
02) Consider a hydrostatic system represented by the thermodynamic variables volume V, pressure P and temperature T. A) A hydrostatic system undergoes a phase transition from first order to temperature To = 300 K and pressure Po = 1 x 100 Pa. In this case, it is verified that the variation of the specific volume of the system Av = 2 x 10 m3/Kg and the variation of the enthalpy specific Ah = 60 KJ/Kg. Determine the variation of the...
In the instant of the figure, two particles move in an xy plane. Particle Pi has...
In the instant of the figure, two particles move in an xy plane. Particle Pi has mass 1.83 kg and speed vi-6.08 m/s, and it is at distance d1 = 8.15 m from point O. Particle P2 has mass 1.68 kg and speed v2 = 4.95 m/s, and it is at distance d2 6.86 m from point o. what is the magnitude of the net angular momentum of the two particles about Pi P2 Number Units
1. An experimenter wishes to generate in air a sound wave that has a displacement amplitude...
1. An experimenter wishes to generate in air a sound wave that has a displacement amplitude of 5.70 x 10-6 m. The pressure amplitude is to be limited to 0.850 Pa. What is the minimum wavelength the sound wave can have? (Take the equilibrium density of air to be p = 1.20 kg/m3 and assume the speed of sound in air is v = 343 m/s.) m 2. A sound wave in air has a pressure amplitude equal to 3.98...
02) Consider a hydrostatic system represented by the thermodynamic variables volume V, pressure P and temperature...
02) Consider a hydrostatic system represented by the thermodynamic variables volume V, pressure P and temperature T. a) Consider entropy S = S(T, V) and derive the equation TdS. Tas = Cvat +T (1) dV. V Show that this equation can be written as follows BT TdS = CydT + PDV where Cv is the thermal capacity at constant volume, B is the isobaric expansiveness and K is isothermal compressibility: b) Consider a gas described by the equation of state...
Hydrostatic Pressure Worksheet 1. Two liquids, 1 and 2, are in equilibrium in a U-tube that...
Hydrostatic Pressure Worksheet 1. Two liquids, 1 and 2, are in equilibrium in a U-tube that is open to air (Po 1 atm- 1.01325 × 105 Pa) at both ends. The liquids do not mix. The density of liquid 2 is 1000 g and the height of it is h2 8 m. The density of the liquid I is p 800 m3 Pl 000 A P2 hi a) What is the pressure at point B (the interface of liquid I...
A tank of water of length 20 m, 10 m, and height 3.8 m is filled...
A tank of water of length 20 m, 10 m, and height 3.8 m is filled with water of density 1.2 g/cm3. Find the pressure (in Pa) of water on one of the walls at a point 165 cm above the bottom. Round off the answer to 2 decimal places.
1- Calculate the net positive suction head (NPSH) of the pump using the following data. i) - Vapo...
1- Calculate the net positive suction head (NPSH) of the pump using the following data. i) - Vapor pressure of liquid -2.685 x 104 Pa i) - Distance between the level of liquid in the reservoir and suction line 1.2 m. The pump is above the liquid level. ii) -The density of liquid 865 kg/m3 iv)- Friction in the suction line 3.5 J/kg v) - Reservoir is open to atmosphere 2- Liquid octane shall be drawn from an open suction...
Ex 2 Please complete the required calculations in the table }p2 V1 V2 P2 theory Lab...
Ex 2
Please complete the required calculations in the table
}p2
V1
V2
P2 theory
Lab 5: Bernaulli's Principle Demonstration Inlet Experimental Experimental Inlet Flow Throat flow Theoretical Volumetric Volumetric Inlet flow rate flow rate pressure pressure Throat speed speed Throat Pressure 2 P2 Theary Error Throat pressurepressure P2 Experiment v1 P1 P1 P2 Experiment Bar m/sec Pascal m3/sec Ba 10.x 20 3.xiOl LOOO FO.48 Water Density 1000 kg/m Venturi throat area (A)-0.000036 m Water temperature Venturi inlet area IA:...
given the information: answer clear and correct 1 Common conversions: 1 hr = 3600 s 1...
given the information:
answer clear and correct
1 Common conversions: 1 hr = 3600 s 1 N = 1 kg*m/s2 1 J = 1 N*m = 1 kg*m/s? 1 W = 1 J/s = 0.738 ft-lb/s 1 hr = 550 ft-lb/s = 746 W 1 kW*h = 3.60x106 J 1 eV = 1.602x10-19 J 1 C = 1 A's 1 V = 1 J/C 12 = 1 VIA 1 A = 1 C/s 1 T = 1 N/A m 1...
given the information answer: clearly and correct 1 Common conversions: 1 hr = 3600 s 1...
given the information
answer: clearly and correct
1 Common conversions: 1 hr = 3600 s 1 N = 1 kg*m/s2 1 J = 1 N*m = 1 kg*m-/s2 1 W = 1 J/s = 0.738 ft-lb/s 1 hr = 550 ft-lb/s = 746 W 1 kW*h = 3.60x106J 1 eV = 1.602x10-19 J 1 C = 1 A's 1 V = 1 J/C 12 = 1 VIA 1 A = 1 C/s 1 T = 1 N/A*m 1 Wb =...
02) Consider a hydrostatic system represented by the thermodynamic variables volume V, pressure P and temperature T. A) A hydrostatic system undergoes a phase transition from first order to temperature To = 300 K and pressure Po = 1 x 100 Pa. In this case, it is verified that the variation of the specific volume of the system Av = 2 x 10 m3/Kg and the variation of the enthalpy specific Ah = 60 KJ/Kg. Determine the variation of the...
In the instant of the figure, two particles move in an xy plane. Particle Pi has mass 1.83 kg and speed vi-6.08 m/s, and it is at distance d1 = 8.15 m from point O. Particle P2 has mass 1.68 kg and speed v2 = 4.95 m/s, and it is at distance d2 6.86 m from point o. what is the magnitude of the net angular momentum of the two particles about Pi P2 Number Units
1. An experimenter wishes to generate in air a sound wave that has a displacement amplitude of 5.70 x 10-6 m. The pressure amplitude is to be limited to 0.850 Pa. What is the minimum wavelength the sound wave can have? (Take the equilibrium density of air to be p = 1.20 kg/m3 and assume the speed of sound in air is v = 343 m/s.) m 2. A sound wave in air has a pressure amplitude equal to 3.98...
02) Consider a hydrostatic system represented by the thermodynamic variables volume V, pressure P and temperature T. a) Consider entropy S = S(T, V) and derive the equation TdS. Tas = Cvat +T (1) dV. V Show that this equation can be written as follows BT TdS = CydT + PDV where Cv is the thermal capacity at constant volume, B is the isobaric expansiveness and K is isothermal compressibility: b) Consider a gas described by the equation of state...
Hydrostatic Pressure Worksheet 1. Two liquids, 1 and 2, are in equilibrium in a U-tube that is open to air (Po 1 atm- 1.01325 × 105 Pa) at both ends. The liquids do not mix. The density of liquid 2 is 1000 g and the height of it is h2 8 m. The density of the liquid I is p 800 m3 Pl 000 A P2 hi a) What is the pressure at point B (the interface of liquid I...
1- Calculate the net positive suction head (NPSH) of the pump using the following data. i) - Vapor pressure of liquid -2.685 x 104 Pa i) - Distance between the level of liquid in the reservoir and suction line 1.2 m. The pump is above the liquid level. ii) -The density of liquid 865 kg/m3 iv)- Friction in the suction line 3.5 J/kg v) - Reservoir is open to atmosphere 2- Liquid octane shall be drawn from an open suction...
Ex 2
Please complete the required calculations in the table
}p2
V1
V2
P2 theory
Lab 5: Bernaulli's Principle Demonstration Inlet Experimental Experimental Inlet Flow Throat flow Theoretical Volumetric Volumetric Inlet flow rate flow rate pressure pressure Throat speed speed Throat Pressure 2 P2 Theary Error Throat pressurepressure P2 Experiment v1 P1 P1 P2 Experiment Bar m/sec Pascal m3/sec Ba 10.x 20 3.xiOl LOOO FO.48 Water Density 1000 kg/m Venturi throat area (A)-0.000036 m Water temperature Venturi inlet area IA:...
given the information:
answer clear and correct
1 Common conversions: 1 hr = 3600 s 1 N = 1 kg*m/s2 1 J = 1 N*m = 1 kg*m/s? 1 W = 1 J/s = 0.738 ft-lb/s 1 hr = 550 ft-lb/s = 746 W 1 kW*h = 3.60x106 J 1 eV = 1.602x10-19 J 1 C = 1 A's 1 V = 1 J/C 12 = 1 VIA 1 A = 1 C/s 1 T = 1 N/A m 1...
given the information
answer: clearly and correct
1 Common conversions: 1 hr = 3600 s 1 N = 1 kg*m/s2 1 J = 1 N*m = 1 kg*m-/s2 1 W = 1 J/s = 0.738 ft-lb/s 1 hr = 550 ft-lb/s = 746 W 1 kW*h = 3.60x106J 1 eV = 1.602x10-19 J 1 C = 1 A's 1 V = 1 J/C 12 = 1 VIA 1 A = 1 C/s 1 T = 1 N/A*m 1 Wb =...
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