Question

Chapter 4/Worksheet E: Limiting Reagents and Percent Yield Name Rec. Section Number: Group Name If you start with 30 g ammonium nitrate and 50 g sodium phosphate Balance the reaction. What is the limiting reactant? a. b. c. d. How many grams of NaNO, would you make? How much of the excess reactant was used up? d. how much of the excess reactant was left over? Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 2. If you started with 30.0 g of H2S and 50.0 g of O, how many grams of s, would be produced assuming 68% yield? 51

Answer 1

Part a Balance chemical equation 3 NH_4 NO_3 + NO_3 PO_4 rightsinglearrow (NH_4)_3 PO_4 + 3 NaNo_3 According balance chemical equation (S.C.) stoichiometry co efficient of the following reactants and products. NH_4NO_3 rightsinglearrow 3 Na_3Po_4 rightsinglearrow 1 (NH_4)_3PO_4 rightsinglearrow 1 NaNo_3 rightsinglearrow 1 Part b rightsinglearrow limiting reagent rightsinglearrow reactant which is consumed firstly in reaction. Rules of calculating limiting reagent 1) first find the number of moles of reactants if what is given - moles of NH_4No_3 rightsinglearrow given weight/molar mass (mm) rightsinglearrow 30/80 mole (mm of mm) moles of NH_3Po_4 rightsinglearrow given weight/molar mass \r\n = 50/164 mole. 2) After moles calculation, moles of reactants divided by stoichimetry co efficient respectively and observe for NH_4NO_3 rightsinglearrow 3/8/3 = 1/8 = 0.125 fro Na_3PO_4 rightsinglearrow 50/164 = 0.30 According to calculation NH_4NO_3 has minimum value i.e NH_4NO_2 is limiting reagent and Na_3po_4 is excess reagent. Part c