ch 14 reg hw: 5) When 0.0034 moles of a weak acid are dissolved in enough...
ch 14 reg hw:
5) When 0.0034 moles of a weak acid are dissolved in enough water to make 0.500 L, the pH of the resulting solution is 5.86. Calculate Ka.
23) Phenol (C6H5OH, also called carbolic acid) has a pKa of 9.89. It is used to preserve body tissues and is quite toxic. Calculate the percent ionized in 0.0789 M phenol--a dilute solution.
Homework Answers
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ch 14 reg hw:
5) When 0.0034 moles of a weak acid are dissolved in enough...
when 0.45 moles of a weak acid are dissolved in enough water to make 0.800 L...
when 0.45 moles of a weak acid are dissolved in enough water to make 0.800 L the pH of the resulting solution is 5.27. calculate Ka
a. Enough of a monoprotic acid is dissolved in water to produce a 0.0163 M solution....
a. Enough of a monoprotic acid is dissolved in water to produce
a 0.0163 M solution. The pH of the resulting solution is 2.51.
Calculate the Ka for the acid. Ka= ________
It's not 5.86 10-4. I tried it and it
wasn't correct.
b. The Ka of a monoprotic weak
acid is 6.61 × 10-3. What is the percent ionization of a 0.108 M
solution of this acid? Percent ionization= ___________
it's not 24.72 %. I tried it's also incorrect.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0183 M solution....
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0183 M solution. The pH of the resulting solution is 2.47. Calculate the pKa for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0106 M solution....
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0106 M solution. The pH of the resulting solution is 2.69. Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0165 M solution....
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0165 M solution. The pH of the resulting solution is 2.34 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0113 M solution....
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0113 M solution. The pH of the resulting solution is 2.64 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0140 M solution....
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0140 M solution. The pH of the resulting solution is 2.50. Calculate the Ką for the acid. Ka =
Questiull 14 UI 20 Enough of a monoprotic weak acid is dissolved in water to produce...
Questiull 14 UI 20 Enough of a monoprotic weak acid is dissolved in water to produce a 0.0151 M solution. The pH of the resulting solution is 2.52. Calculate the K, for the acid. Kx = 6 x10-4
1. A weak monoprotic acid has molar mass 180 g/mol. When 1.00 g of this acid is...
1. A weak monoprotic acid has molar mass 180 g/mol. When 1.00 g of this acid is dissolved in enough water to obtain a 300 mL solution, the pH of the resulting solution is found to be 2.62. What is the value of Ka for this acid? 2. A weak monoprotic acid has pKa = 3.08. Calculate the percent ionization of a 0.35 M solution of this acid. 3. Calculate the pH of a solution that is 0.050 M in CH3COOH...
Strong base is dissolved in 585 mL of 0.600 M weak acid (Ka=3.46×10−5) to make a...
Strong base is dissolved in 585 mL of 0.600 M weak acid (Ka=3.46×10−5) to make a buffer with a pH of 4.17 Assume that the volume remains constant when the base is added. HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) Calculate the pKa value of the acid, and determine the number of moles of acid initially present. pKa= initial amount: mol HA When the reaction is complete, what is the concentration ratio of conjugate base to acid? [A−]/[HA]= How many moles of strong base were initially...
a. Enough of a monoprotic acid is dissolved in water to produce
a 0.0163 M solution. The pH of the resulting solution is 2.51.
Calculate the Ka for the acid. Ka= ________
It's not 5.86 10-4. I tried it and it
wasn't correct.
b. The Ka of a monoprotic weak
acid is 6.61 × 10-3. What is the percent ionization of a 0.108 M
solution of this acid? Percent ionization= ___________
it's not 24.72 %. I tried it's also incorrect.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0140 M solution. The pH of the resulting solution is 2.50. Calculate the Ką for the acid. Ka =
Questiull 14 UI 20 Enough of a monoprotic weak acid is dissolved in water to produce a 0.0151 M solution. The pH of the resulting solution is 2.52. Calculate the K, for the acid. Kx = 6 x10-4
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