when 0.45 moles of a weak acid are dissolved in enough water to make 0.800 L...
ch 14 reg hw: 5) When 0.0034 moles of a weak acid are dissolved in enough water to make 0.500 L, the pH of the resulting solution is 5.86. Calculate Ka. 23) Phenol (C6H5OH, also called carbolic acid) has a pKa of 9.89. It is used to preserve body tissues and is quite toxic. Calculate the percent ionized in 0.0789 M phenol--a dilute solution.
8a) 0.263 moles of para-aminobenzoic acid (HC,H.NO2) are dissolved in enough water to make a final volume of 2.0 L. The resulting solution has a pH of 2.58. What is the hydronium ion concentration of the solution? a. 0.132 M b.0.13 M c. 0.88 M d.0.00263M a. Ob. O c. Od. 8b) 0.263 moles of para-aminobenzoic acid (HC,H.NO,) are dissolved in enough water to make a final volume of 2.0 L. The resulting solution has a pH of 2.58. What...
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0106 M solution. The pH of the resulting solution is 2.69. Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0165 M solution. The pH of the resulting solution is 2.34 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0113 M solution. The pH of the resulting solution is 2.64 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0140 M solution. The pH of the resulting solution is 2.50. Calculate the Ką for the acid. Ka =
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0183 M solution. The pH of the resulting solution is 2.47. Calculate the pKa for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0180 M solution. The pH of the resulting solution is 2.63. Calculate the K, for the acid. K =
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0182 M solution. The pH of the resulting solution is 2.40, Calculate the K, for the acid. K.=
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0181 M solution. The pH of the resulting solution is 2.41. Calculate the K, for the acid. KE 9.58 x10--