Answer
Kc = 1.1
Explanation
A + 2B ----> C
Kc = [C]/([A][B]2)
Initial concentration
[A] = 0.54
[B] = 0.71
[C] = 1.2
change in concentration
[A] = -x
[B] = -2x
[C] = +x
Equillibrium concentration
[A] = 0.54 - x
[B] = 0.71 - 2x
[C] = 1.2 + x
at equillibrium
[C] = 1.0
1.2 + x = 1.0
x = - 0.2
[A] = 0.54 - (-0.2) = 0.74M
[B] = 0.71 - (2 × (-0.2)) = 1.11M
Kc = 1.0/(0.74×(1.11)2)
Kc = 1.1
ast x 0 13.7 Equilibrium Calculations: /X- + courses/20647/assignments/93049 Dashboard CAUStream TV and M...Outlook Admissions Proce....