Question

Predict/Calculate Problem 6.41 8 of 8 IP A 3.50-kg block on a smooth tabletop is attached by a string to a hanging block of mass 2.80 kg, as shown in the figure. The blocks are released from rest and allowed to move freely. (Figure 1) Part B Find the acceleration of the blocks m/s2 Submit Request Answer Part C Figure 1 of 1 Find the tension in the string. 3.50kg Submit Request Answer

Answer 1

Mass of the block, m1 = 3.5 kg

Hanging mass,m2 = 2.8 kg

The Net force on m1 is

m1 a = T------(1)

Net force on m2 is

m2 a = m2 g - T

m2 a = m2 g - m1 a   [fromeq(1)]

a = m2 g/(m1 +m2)

   = 2.8 kg *9.8 m/s^2 /(3.5 kg +2.8 kg)

a = 4.35 m/s^2 is the acceleration of the blocks

since T = m1 a = 3.5 kg *4.35 m/s^2

T = 15.22 N is the tension in the string