Question

Problem #4: -5 ft . 5 ft . 5 ft 5 ft 11.5k 8 ft

For the following trusses determine the forces in all members using the method of joints. Specify whether the member is in tension or compression.

Answer 1

1.2.loso -0-7512 05:34 -0.937k 1 V E ht HE HA s VE & 10 ft Flom fig tand=&=&= 38.66% O = Go - a = 51.34 Resolve the force 1.2k. {v=O TVE = 1 VA + VE = 1.5 +0.937 - 2.437k EMA=0 VEX 20 = 1.5X10 +0.937 x 15 -0.7584 VE = 1.3027k VA = 1-134 k

To find HA & HE SH=0 HA HE to HE to .75= Mc=o. (Right hand side) HEX 8 + 0.7584 +0.93785 E VE X10 HE = 0.667 K HA=0.6674o.lt HA= 1.417. loint A FABSTM38.66 =1.134 A 38.66 FAB= 1.8152 K (C) Ya 1-417 | 1.134 FB L = FAB B Toint Joint FBC=1.8152 K (C) ta FB4 = 0 Joint a FAG=0 fcq=0 A 9

joint E FDE S1038.66 = 1.3027 3660 RDE 2.085k (C) L 0.667 1.3027 FDE (OS 38.66 +FFE = 0667 FEF = 0.961 KT) Totut D 1.2 FDF = 1.2K (C) 2085 FCD = 2.085k (c)