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At what angle will the second-order maximum be seen from a diffraction grating of spacing 1.45?m...

At what angle will the second-order maximum be seen from a diffraction grating of spacing 1.45?m when illuminated by light of wavelength 520nm ?

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Answer #1

Apply sin(angle) = m(wavelength)/d

sin(angle) = 2(520 X 10-9)/(1.45 X 10-6)

angle = 45.8o

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