Question

The drop down answers for part A are following: Lewis Acid, or Lewis Base, or Both lewis acid and lewis base, or neither a lewis acid or base.

The drop down answers for part B are the following:( H 1s, C 2p, ), (C 2p, 1s H), (C-H sigma, C 2p) (C 2p, C-H sigma), (NA there are no lewis orbitals.)

Office X Sumn X Lewis × Medi × Trans Comr x Untiti × CHE × Medie X User × Paola C secure https://canvas.ucdavis.edu/courses/140976/quizzes/15835/take Question 3 1 pts The equation below shows an elementary step called a hydride shift. ÇH3 CH3 3 3 1. Using the dropdown menu, indicate the roles of A in the reaction. Both a Lewis Acid and a Lewis B 2. In a Lewis Acid-Base reaction, electrons in a filled orbital of the Lewis base interact with an empty orbital of the Lewis Acid. Fill in the blanks to identify the acidic and basic orbitals involved in the reaction shown. A is the Lewis basic orbital, and is the Lewis acidic orbital. C-H sigma, C 2p

Answer 1

Part-A:    Answer:     Lewis acid

Reason: eventhough there is an internal hydride ion shift, totally the molecule is positvely charged and is ready to accept a pair of electrons, hence it is a Lewis-acid.

Part-B: Answer:      C-H sigma, C 2p

Reason: Since they have asked us first lewis basic orbital which is C-H sigma and then next filling line is about lewis acidic orbital this is only carbon 2p orbital which accepts the hydride ion formed by breaking C-H sigma bond and is transferred to 2p orbital of carbon.

Thank You So Much! Please Rate this answer as you wish.